$$f(x)=$$|⌈x]x| in −$$1$$≤x≤$$2$$ is

Correct option is 1continuous at x = 0

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$f (x) = | ⌈ x] x | in - 1 \leq x \leq 2 is$

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continuous at x = 0

discontinuous at x = 0

differentiable at x = 0

continuous at x = 2

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detailed solution

Correct option is A

limx→0−f(x)limx→0+f(x)=0=f(0)∴f is continuous at x=0.

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f(x)=|⌈x]x| in −1≤x≤2 is

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$f (x) = | ⌈ x] x | in - 1 \leq x \leq 2 is$