Q.
f(x)=xlogexmonotonically decreases in
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a
(0,1/e)
b
(1/e,1)
c
(1,∞)
d
(1/e,∞)
answer is A.
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Detailed Solution
f(x)=xlogex For g(x)=x logex,g′(x)=x1x+logex=1+logexThus, g (x) increases for 1e,∞and decreases for 0,1e. From the graph,f(x)=xlogex decreases in 0, 1e.
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