f(x,y)=x2+y2+2ax+2by+c=0 represents a circle. If f(x,0) = 0 has equal roots, each being 2, and f(0,y) = 0 has 2 and 3 as its roots, then the center of the circle is
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a
(2,52)
b
Data are not sufficient
c
(−2,−52)
d
Data are inconsistent.
answer is D.
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Detailed Solution
x2+2ax+c=(x−2)2 or −2a=4,c=4 or a=−2,c=4 y2+2by+c=(y−2)(y−3) or −2b=5,c=6 or b=−52,c=6 Clearly, the data are not consistent.