The false statement in the following is
p∧(~p) is a contradiction
(p⇒q)⇔(~q⇒∼p) is a contradiction
~(~p)⇔p is a tautology
p∨(~p) is a tautology
p⇒q is logically equivalent to ~q⇒∼p
(p⇒q)⇔(~q⇒∼p)
is a tautology but not a contradiction.