Q.

A father has 3 children with at least one boy. The probability that he has 2 boys and 1 girl is

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a

1/4

b

1/3

c

2/3

d

None of these

answer is B.

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Detailed Solution

Consider the following events:A: Father has at least one boy.B: Father has 2 boys and one girlThen,A = one boy and2 girls, 2 boys and one girl, 3 boys and no girlA∩B = 2 boys and one girlNow, the required probability is=P(A/B)=P(A∩B)P(A)=13
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