First slide

Combinations

Question

A father with 8 children takes them 3 at a time to the zoological gardens, as often as he can without taking the same 3 children together more than once. The number of times he will go the garden, is

Easy

A

336
B

112
C

56
D

None of these

Solution

The number of times he will go to the garden is same as the number of selecting 3 children from 8.
Therefore, the required number of ways $=^{8} C_{3} = 56$

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