Q.
Find the area bounded by y=x3−x and y=x2+x
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a
37square units
b
372square units
c
373square units
d
374square units
answer is B.
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Detailed Solution
y=x3−x=x(x−1)(x+1) is a cubic polynomial function intersecting the x -axis at (−1,0),(0,0),(1,0) . y=x2+x=x(x+1) is a quadratic function which is concave upward and intersect x -axis at (−1,0)(0,0) . The graphs of curves are as shown in following figure. From the figure, Requiredarea =∫−10 x3−x−x2+xdx+∫02 x2+x−x3−xdx =∫−10 x3−x2−2xdx+∫02 x2+2x−x3dx =x44−x33−x2−10+x33+x2−x4402 =0−14+13−1+83+4−4 =3712 sq. units
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