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By Expert Faculty of Sri Chaitanya
a
323+4π sq units
b
163+4π sq units
c
323+16π sq units
d
323+8π sq units
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Correct option is A
Solving the curves, we get x2+4x=8x⇒x=0,4=∫04 yparabola dx+∫48 ycircle dxA=∫04 2xdx+4π =43x3/204+4π =43×44+4π=323+4π square units
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