Find the area, lying above the x -axis and included between the circle x2+y2=8x and the parabola y2=4x

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323+4π sq units

163+4π sq units

323+16π sq units

323+8π sq units

answer is A.

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Detailed Solution

Solving the curves, we get x2+4x=8x⇒x=0,4=∫04 yparabola dx+∫48 ycircle dxA=∫04 2xdx+4π =43x3/204+4π =43×44+4π=323+4π square units

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