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a
logsint+12+sin2t+sint+c
b
logsint+12+sin2t−sint+c
c
logsint+sin2t+sint+c
d
logsint−12+sin2t+sint+c
answer is A.
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Detailed Solution
∫cosect−1dt=∫1−sintsintdt=∫1−sint1+sintsint(1+sint)dt Use =∫1y2−a2=logy+y2−a2+c=∫costsin2t+sintdt Put sint=y=∫dyy2+y=∫dyy+122−122+c=logy+12+y2+y+c=logsint+12+sin2t+sint+c