Find the mean deviation about the mean for the following data6,7,10,12,13,4,8,12
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is 2.75.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Mean of the given data is x =6+7+10+12+13+4+8+128=728=9 The deviation of the respective observations from the mean x, is xi-x are 6-9,7-9,10-9,12-9,13-9,4-9,8-9,12-9 or -3,-2,-1,3,4,-5,-1,3 The absolute values of the deviations, xi-x are 3,2,1,3,4,5,1,3 The required mean deviation about the mean is M.D.(x)=∑ i=18 xi-x8=3+2+1+3+4+5+1+38 =228 =2.75