Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Find the mean deviation about the mean for the following data6,7,10,12,13,4,8,12

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

answer is 2.75.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Mean of the given data is  x =6+7+10+12+13+4+8+128=728=9 The deviation of the respective observations from the mean x, is xi-x are 6-9,7-9,10-9,12-9,13-9,4-9,8-9,12-9 or -3,-2,-1,3,4,-5,-1,3 The absolute values of the deviations,  xi-x are 3,2,1,3,4,5,1,3 The required mean deviation about the mean is  M.D.(x)=∑  i=18 xi-x8=3+2+1+3+4+5+1+38 =228 =2.75
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon