Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Find the mean deviation about the median for the following data; 3, 9, 5, 3, 12, 10, 18, 4, 7 , 19, 21

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

answer is 5.75.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Here, the number of observations is11 which is odd. Arranging the data into ascending order, we get 3,3, 4, 5,7 ,9, 10, 12, 18, 19,21 Median =11+12th  or 6th  observation =9The absolute values of the respective deviations from the median  i.e., xi−M are: 6,6,5,4,2,0,1,3,9,10,12 Therefore, ∑i=111 xi−M=58 and M.D. (M)=111∑i=111 xi−M=111×58=5.27
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
personalised 1:1 online tutoring