Permutations

Question

Find the number of zeros (cyphers) at the end of 100!

Difficult

Solution

${\mathrm{E}}_{5}(100!)=\left[\frac{100}{5}\right]+\left[\frac{100}{25}\right]=24$

There are 24 zeros at the end of 100!

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Download Now