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Questions  

 Find the range of f(x)=cot12xx2 . 

a
π4,π
b
π4,π
c
π2,π
d
-π,π2

detailed solution

Correct option is A

Let θ=cot−1⁡2x−x2, where θ∈(0,π)⇒ cot⁡θ=2x−x2, where θ∈(0,π)⇒ cot⁡θ=1−1−2x+x2, where θ∈(0,π) ⇒cot⁡θ=1−(1−x)2, where θ∈(0,π)⇒ cot⁡θ≤1, where θ∈(0,π) ⇒ π4≤θ<π  So, the range of f(x) is π4,π .

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