First slide
Functions (XII)
Question

 Find the range of f(x)=cot12xx2 . 

Moderate
Solution

  Let θ=cot12xx2, where θ(0,π) cotθ=2xx2, where θ(0,π) cotθ=112x+x2, where θ(0,π) ⇒cotθ=1(1x)2, where θ(0,π) cotθ1, where θ(0,π) ⇒ π4θ<π  So, the range of f(x) is π4,π . 

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