Find the range of f(x)=cot−12x−x2 .
π4,π
π2,π
-π,π2
Let θ=cot−12x−x2, where θ∈(0,π)⇒ cotθ=2x−x2, where θ∈(0,π)⇒ cotθ=1−1−2x+x2, where θ∈(0,π) ⇒cotθ=1−(1−x)2, where θ∈(0,π)⇒ cotθ≤1, where θ∈(0,π) ⇒ π4≤θ<π So, the range of f(x) is π4,π .