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Find the range of f(x) $f (x) = \sin^{- 1} [x]$

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−π2,0

−π2,0,π2

−π2,π2

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detailed solution

Correct option is A

f(x)=sin−1[x] is defined if −1≤[x]≤1 or [x]=−1,0,1 or x∈[−1,2) So, range is sin−1⁡(−1),sin−1⁡0,sin−1⁡1≡{−π/2,0,π/2}

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Find the range of f(x) f(x)=sin−1[x]

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Find the range of f(x) $f (x) = \sin^{- 1} [x]$