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Find the sum to infinity  of the series 1+23+632+1033+1434+...... is 

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2
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detailed solution

Correct option is B

Let S=1+23+632+1033+1434+….(1)13S=13+232+633+1034+…...(2) Subtracting (2) from (1) S1−13=1+13+432+433+434+…..S23=43+4321+13+132+…..23S=43+43211−13=43+432,32=2∴S=3


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