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Find  the sum to n terms of the series 1/1×3+1/3×5+15×7+.....

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a
nn+1
b
n2n+1
c
n3n+1
d
n5n+1

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detailed solution

Correct option is B

Let T be the rth term of the given series. Then, Tr=1(2r−1)(2r+1),r=1,2,3…n=1212r−1−12r+1 Hence, the required sum is ∑i=1n Tr=1211−13+13−15+15−17+…...+12n−1−12n+1=121−12n+1=n2n+1


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