Find the sum of the series ∑k=1360 1kk+1+(k+1)k
1918
1819
1718
1618
Tk=1kk+1k+k+1=k+1−kkk+1=1k−1k+1∴S=∑k=1360 1k−1k+1=1−1361=1−119=1819