Q.

Find the sum of the series ∑k=1360 1kk+1+(k+1)k

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a

1918

b

1819

c

1718

d

1618

answer is B.

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Detailed Solution

Tk=1kk+1k+k+1=k+1−kkk+1=1k−1k+1∴S=∑k=1360 1k−1k+1=1−1361=1−119=1819
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