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 Find the sum of the series k=13601kk+1+(k+1)k

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a
1918
b
1819
c
1718
d
1618

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detailed solution

Correct option is B

Tk=1kk+1k+k+1=k+1−kkk+1=1k−1k+1∴S=∑k=1360 1k−1k+1=1−1361=1−119=1819


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