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The first and last terms of an A.P. are a and l respectively. If s is the sum of all the terms of the A.P., then the common difference of the A.P. is

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a
l2−a2s−(l+a)
b
l2−a22s−(l+a)
c
l2+a22s−(l+a)
d
l2+a2s−(l−a)

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detailed solution

Correct option is B

Let n be the number of terms. Then s=n2(a+l)⇒n=2sa+lAlso, d=l−an−1=(l−a)(l+a)2s−(l+a)=l2−a22s−(l+a)


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