Five different games are to be distributed among 4 children randomly. The probability that each child get at least one game is

Total number of ways of distribution is 45∴ n(S)=45Total number of ways of distribution so that each child gets at least one game is 45−4C135+4C225−4C3=1024−4×243+6×32−4= n(E)=240Therefore, the required probability is n(E)n(S)=24045=1564