Questions
Five different marbles are placed in 5 different boxes randomly. Then the probability that exactly two boxes remain empty is (each box can hold any number of marbles)
detailed solution
Correct option is B
We have,n(S)=55For computing favorable outcomes, 2 boxes which are to remain empty, can be selected in 5C2 ways and 5 marbles can be placed in the remaining 3 boxes in groups of 221 or 311 in3!5!2!2!2!+5!3!2!=150 ways ⇒ n(A)=5C2×150Hence,P(E)=5C2×15055=60125=1225Talk to our academic expert!
Similar Questions
A bag contains 10 different balls. Five balls are drawn simultaneously and then replaced and then seven balls are drawn. If the probability that exactly three balls are common to the two draws is p, then the value of 8p is ________.
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