A flagstaff stands at the center of a rectangular field whose diagonal is 1200m, and subtends angles  150and 450  at the mid points of the sides of the field. The height of the flagstaff is

Let OP be the flagstaff of height ‘h’ standing at the center O of the rectangular field ABCD subtending angles  150and 450  at E the F, the mid points of the sides AD and DC of the field .Then  OE=hcot150=h2+3 and OF=hcot450=h⇒EF=h12+2+32=2h2+3⇒1200=AC=2EF=4h2+3⇒h=3002+3=3002−3