Q.

The foci of the ellipse  x216+y2b2=1  and the hyperbola x2144−y281=125  coincide, then b2  is

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a

1

b

5

c

7

d

9

answer is C.

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Detailed Solution

Foci of the ellipse =(±16−b2,0) Foci of the hyperbola =(±14425+8125,0)=(±3,0)     Both are equal if b2=7
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