Story
NEET AITS
Story
Mock Tests
Story
Live Class
Story
JEE AITS

Questions  

The focus of the parabola 4y2+12x20y+67=0 

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
(−7/2,5/2)
b
(– 3/4, 5/2)
c
(– 17/4, 5/2)
d
(5/2, – 3/4)

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is C

The given equation of the parabola can be written as  y2−5y=−3x−67/4⇒(y−5/2)2=−3(x+7/2)⇒Y2=4aX where Y=y−5/2,X=x+7/2and a=−3/4The focus of Y2=4aX is (X,Y)=(a,0)=(−3/4,0)⇒x+7/2=−3/4,y−5/2=0⇒x=−17/4,y=5/2Therefore, required focus is (– 17/4, 5/2)
ctaimg

ctaimg

Similar Questions

The  length of the latus rectum of the parabola 289(x3)2+(y1)2=(15x8y+13)2  is equal to

Want to Improve your productivity
talk to our academic experts now !!

counselling
india
+91

whats app icon