First slide
Parabola
Question

The focus of the parabola 4y2+12x20y+67=0 

Moderate
Solution

The given equation of the parabola can be written as  

y25y=3x67/4(y5/2)2=3(x+7/2)

Y2=4aX where Y=y5/2,X=x+7/2and a=3/4

The focus of Y2=4aX is (X,Y)=(a,0)=(3/4,0)

x+7/2=3/4,y5/2=0x=17/4,y=5/2

Therefore, required focus is ( 17/4, 5/2)

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