Four cards are drawn from pack successively without replacement, the probability of getting first king, second queen , third Ace and Fourth jack is

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6452×51×50

256(52)4

25652×51×50×49

4×3×2×152×51×50×49

answer is C.

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Detailed Solution

452×451×450×449=25652×51×50×49 p(k∩j∩Q∩A)=PK×PJ×PQ×PA

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