Four numbers n1,n2,n3 and n4 are given as n1=sin⁡15∘−cos⁡15∘,n2=cos⁡93∘+sin⁡93∘,n3=tan⁡27∘−cot⁡27∘,n4=cot⁡127∘+tan⁡127∘ then

n1=sin⁡15∘−cos⁡15∘<−ve          cos⁡15∘>sin⁡15∘n2=cos⁡93∘+sin⁡93∘                     cos⁡3∘>sin⁡3∘=−sin⁡3∘+cos⁡3∘>0                  tan⁡27∘