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Questions  

From a point P, perpendiculars PM and PN are drawn to x and y axes, respectively. If MN passes through fixed point (a,b), then locus of P is  

a
xy=ax+by
b
xy=ab
c
xy=bx+ay
d
x+y=xy

detailed solution

Correct option is C

Let Ph,kSo, points M and N are h,0 and 0,k, respectively.MN passes through the point Qa,b∴  So, M,N and Q are collinear.∴   −kh=b−0a−h∴     ak−hk=−bhso locus is bx+ay=xy

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