From a point (sinθ,cosθ) , if three normals can be drawn to the parabola y2=4ax, then the value of a is
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a
(1/2,1)
b
[−1/2,0)
c
[−1/2,1]
d
(−1/2,0)∪(0,1/2)
answer is D.
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Detailed Solution
Point (sinθ,cosθ) lies on the circle x2+y2=1∀θ∈R Now, three normals can be drawn to the parabola y2=4ax if x=|2a| meets this circle. Hence, we must have cosθ>|2a| or 0<|2a|<1 or 0<|a|<12 or a∈−12,0∪0,12