Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A function is defined as fx=limn→∞  cos2nx,         if  x<01+xnn,       if  0≤x≤111+xn,        if x>1which of the following does not hold good?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

Continuous at x = 0 but discontinuous at x = 1

b

Continuous at x = 1 but discontinuous at x = 0

c

Continuous both at x = 1 and x = 0

d

Discontinuous both at x = 1 and x = 0

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

f0-=limn→∞  limn→0-  cos2xn               = a  value  lesser  than  1∞=0f0+= limn→∞  limn→0+  1+xn1n=1Also, f(0) = 1. So, the function is discontinuous at x = 0.Further,  f1-=1;  f1+=0;  f1=1.So, the function is discontinuous at x = 1.
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring