Q.
A function is defined as fx=limn→∞ cos2nx, if x<01+xnn, if 0≤x≤111+xn, if x>1which of the following does not hold good?
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a
Continuous at x = 0 but discontinuous at x = 1
b
Continuous at x = 1 but discontinuous at x = 0
c
Continuous both at x = 1 and x = 0
d
Discontinuous both at x = 1 and x = 0
answer is A.
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Detailed Solution
f0-=limn→∞ limn→0- cos2xn = a value lesser than 1∞=0f0+= limn→∞ limn→0+ 1+xn1n=1Also, f(0) = 1. So, the function is discontinuous at x = 0.Further, f1-=1; f1+=0; f1=1.So, the function is discontinuous at x = 1.
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