The function f:[2,∞)→(0,∞) defined by f(x)=x2-4x+a, then the set of values of 'a' for which f(x) becomes onto is
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a
(4,∞)
b
[4,∞)
c
{4}
d
ϕ
answer is D.
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Detailed Solution
f(x)=x2−4x+a always attains its minimum value zero. The codomain starts from zero and it is increasing function from x>2fx=x-22+a-4. Minimum value is zero, hence a-4=0a=4