Q.

The function f:[2,∞)→(0,∞) defined by f(x)=x2-4x+a, then the set of values of 'a' for which f(x) becomes onto is

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a

(4,∞)

b

[4,∞)

c

{4}

d

ϕ

answer is D.

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Detailed Solution

f(x)=x2−4x+a always attains its minimum value zero.  The codomain starts from zero and it is increasing function from x>2fx=x-22+a-4. Minimum value is zero, hence a-4=0a=4
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