A function f from integers to integers is defined as f(x)=n+3,n∈oddn2,n∈even Suppose k∈ odd and f(f(f(k)))=27, then the sum of digits of k is
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answer is 6.
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Detailed Solution
∵k∈odd f(x)=k+3 f(f(k))=k+32 Ifk+32∈odd⇒27=k+32+3 k=45 not possible.Now,letk+32∈even∴ 27=f(f(f(k)))=f(k+32)=k+34∴ k=105verifying f(f(f(105)))=f(f(108))=f(54)=27∴k=105Hence, sum of digits of k = 1 + 0 +5 = 6