First slide

Functions (XII)

Question

The function $f : N \to N (N is the set of natural numbers)$ defined by $f (n) = 2 n + 3$ is

Easy

A

surjective only
B

injective only
C

bijective
D

none of these

Solution

$f : N \to N, f (n) = 2 n + 3$ Here, the range of the function is $\{5, 6, 7, . . . . .\}$ or $N - \{1, 2, 3, 4\},$ which is a subset of N (co-domain).
Hence, $f (n)$ is injective only.

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