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Q.

The function f:R∼{0}→R    f(x)=1x−2e2x−1  can be made continuous at x=0  by defining f(0)  as:

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a

2

b

−1

c

0

d

1

answer is D.

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Detailed Solution

f(0)=RHL          =limx→0+f(x)=limh→0f(0+h)          =limh→0(1h−2e2h−1)          =limh→0(e2h−1−2h)h(e2h−1)2h.2h          =limh→0e2h−1−2h2h2limh→0(2he2h−1)         =limh→0(1+2h+(2h)22!+...)−1−2h2h2.1         =1
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The function f:R∼{0}→R    f(x)=1x−2e2x−1  can be made continuous at x=0  by defining f(0)  as: