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The function f : R → R defined by, f (x) = 4^x + 4^|x| is

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detailed solution

Correct option is A

Since, for different x, 4x and 4| x | are different positive numbers,∴ f is one–one. Also, f is not onto as its range (0, ∞) is a proper subset of its co-domain R.

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The function f : R → R defined by, f (x) = 4x + 4|x| is

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The function f : R → R defined by, f (x) = 4^x + 4^|x| is