The function f : R → R defined by, f (x) = 4x + 4|x| is
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a
one-one and into
b
many-one and into
c
one-one and onto
d
many-one and onto
answer is A.
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Detailed Solution
Since, for different x, 4x and 4| x | are different positive numbers,∴ f is one–one. Also, f is not onto as its range (0, ∞) is a proper subset of its co-domain R.