The function f satisfies the functional equation 3f(x)+2fx+59x−1=10x+30 for all real x≠1. The value of f(7) is
8
4
-8
11
3f(x)+2fx+59x−1=10x+30
x=7,3f(7)+2f(11)=70+30=100
x=11,3f(11)+2f(7)=140f(7)−20=f(11)−220=−19−4⇒f(7)=4