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Q.

The function f satisfies the functional equation 3f(x)+2fx+59x−1=10x+30 for all real x≠1. The value of f(7) is

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a

8

b

4

c

-8

d

11

answer is B.

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Detailed Solution

3f(x)+2fx+59x−1=10x+30x=7,3f(7)+2f(11)=70+30=100x=11,3f(11)+2f(7)=140f(7)−20=f(11)−220=−19−4⇒f(7)=4

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