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Questions  

 The function f satisfies the functional equation 3f(x)+2fx+59x1=10x+30 for all real x1. The value of f(7) is

a
8
b
4
c
-8
d
11

detailed solution

Correct option is B

3f(x)+2fx+59x−1=10x+30x=7,3f(7)+2f(11)=70+30=100x=11,3f(11)+2f(7)=140f(7)−20=f(11)−220=−19−4⇒f(7)=4

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