First slide
Introduction to integration
Question

The function f whose graph passes through

(0,7/3) and whose derivative is x1x2  isgiven by

Easy
Solution

f(x)=x1x2dx=12(2x)1x2dx=131x23/2+C

So 7/3=1/3+CC=8/3

Therefore f(x)=(1/3)1x23/28

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