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Questions  

The function f whose graph passes through

(0,7/3) and whose derivative is x1x2  isgiven by

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a
f(x)=(1/3)1−x23/2+7
b
f(x)=(3/2)sin−1⁡x+6
c
f(x)=−(1/3)1−x23/2−8
d
f(x)=−(2/3)1−x23/2−8

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detailed solution

Correct option is C

f(x)=∫x1−x2dx=−12∫(−2x)1−x2dx=−131−x23/2+CSo 7/3=−1/3+C⇒C=8/3Therefore f(x)=−(1/3)1−x23/2−8


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