The function f whose graph passes through (0 ,0 )
and whose derivative is cos4x+sin4xcos2x−sin2x is given by
14log1+tanx1−tanx+12sinxcosx
logcosx+sinxcosx−sinx+sin2x
logcosx−sinxcosx+sinx+12sinxcosx+x
none of these
We have
f(x)=∫cos4x+sin4xcos2x−sin2xdx
Using, 2cos4x+sin4x
=cos2x+sin2x2+cos2x−sin2x2, we can write
f(x)=12∫1cos2x−sin2xdx
+12∫cos2x−sin2xdx
=12∫sec2xdx+12∫cos2xdx
=14logtanx+π4+14sin2x+C
=14log1+tanx1−tanx+12sinxcosx+C
Since f(0)=0 , we get C= 0.