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The function f whose graph passes through (0 ,0 )

and whose derivative is cos4x+sin4xcos2xsin2x is given by 

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a
14log⁡1+tan⁡x1−tan⁡x+12sin⁡xcos⁡x
b
log⁡cos⁡x+sin⁡xcos⁡x−sin⁡x+sin⁡2x
c
log⁡cos⁡x−sin⁡xcos⁡x+sin⁡x+12sin⁡xcos⁡x+x
d
none of these

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detailed solution

Correct option is A

We have f(x)=∫cos4⁡x+sin4⁡xcos2⁡x−sin2⁡xdxUsing, 2cos4⁡x+sin4⁡x=cos2⁡x+sin2⁡x2+cos2⁡x−sin2⁡x2, we can write  f(x)=12∫1cos2⁡x−sin2⁡xdx                               +12∫cos2⁡x−sin2⁡xdx=12∫sec⁡2xdx+12∫cos⁡2xdx=14log⁡tan⁡x+π4+14sin⁡2x+C=14log⁡1+tan⁡x1−tan⁡x+12sin⁡xcos⁡x+CSince f(0)=0 , we get C= 0.


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