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Q.

The function f(x)=ae-bx2,x<01,x=0c·cosx,x>0 is differentiable. Then which of the following is not true?

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a

a=c

b

a=1

c

c<0

d

b∈R

answer is C.

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Detailed Solution

f(0−)=f(0)=f(0+)⇒a=1=cf1(0−)=f1(0+)⇒ae−bx2(−2bx)x=0=−sinx at x-0⇒0=0
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