The function
f(x)=cot−1(x+3)x+cos−1x2+3x+1 is defined on the set S, then S is equal to
{-3, 0}
[-3, 0]
[0, 3]
(-3, 0)
For the two components to be meaningful, we must have
x(x+3)≥0 and 0≤x2+3x+1≤1
Hence,
(x+3)x=0 i.e., x=0, −3 ∴ S={−3,0}