The function $$f(x)=e1/x$$−$$1e1/x+1$$,x≠$$0$$ is $$0$$,$$x=0$$

Correct option is 2discontinuous at x = 0

Questions

$The function f (x) = \{\begin{array}{cc} \frac{e^{1 / x} - 1}{e 1 / x + 1}, & x \neq 0 is \\ 0, & x = 0 \end{array}$

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continuous at x = 0

discontinuous at x = 0

discontinuous at but can be made continuous at x = 0

none of these.

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detailed solution

Correct option is B

Here L.H.L.=−1, R.H.L.=1.∴f(x) is discontinuous at x=0.

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The function f(x)=e1/x−1e1/x+1,x≠0 is 0,x=0

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$The function f (x) = \{\begin{array}{cc} \frac{e^{1 / x} - 1}{e 1 / x + 1}, & x \neq 0 is \\ 0, & x = 0 \end{array}$