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The function $f (x) = \frac{\sec^{- 1} x}{\sqrt{x - [x]}},$ where [x] denotes the greatest integer less than or equal to x, is defined for all $x \in$

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R--1,1∪nn∈Z

R+-0,1

R+-n|n∈N

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detailed solution

Correct option is B

The function sec-1x is defined for all x∈R--1,1 and the function 1x-x is defined for all x∈R-zSo, the given function is defined for all x∈R--1,1∪n|n∈Z.

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The function fx=sec-1xx-x, where [x] denotes the greatest integer less than or equal to x, is defined for all x∈

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The function $f (x) = \frac{\sec^{- 1} x}{\sqrt{x - [x]}},$ where [x] denotes the greatest integer less than or equal to x, is defined for all $x \in$