The function fx=sinlogx+1+x2 is
even function
odd function
neither even nor odd
periodic function
fx=sinlogx+1+x2 or f-x=sinlog-x+1x2 =sinlog1+x2-x1+x2+x1+x2+x =sinlog1x+1+x2
=sinlog-logx+1+x2 =-sinlogx+1+x
∴ f-x=-fx
Therefore, f(x) is an odd function.