The function f(x)=1−1−x2 is
Continuous on [−1,1] and differentiable on (−1,1)
Continuous on [−1,1] and differentiable on (−1,0)∪(0,1)
Continuous as well as differentiable on [−1,1]
None of these
f(x)=1−1−x2Clearly, the domain of definition is −1,1.f'(x)=121−1−x2−121−x2−2x=x1−x21−1−x2,Which does not exist for x=0,−1,1Also, f(x) is continuous on −1,1So, (b) is the correct choice.