The function f(x)=(x-3)2 satisfies all the conditions of mean value theorem in 3,4. A point on y=(x-3)2, where the tangent is parallel to the chord joining (3,0) and (4,1) is
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a
72,12
b
72,14
c
1,4
d
4,1
answer is B.
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Detailed Solution
Let the point be x1,y1 . Now slope of the tangent at x1,y1 is 2x1−3 , but it is equal to 1 Therefore, 2x1−3=1⇒x1=72y1=72−32=14 Hence the point is 72,14 .