The function fx=3x-12sinx.ln1+x, x≠0, is continuous at x = 0. Then the value of f(0) is
2loge3
loge32
loge6
none of these
Given fx is continuous at x=0 . Therefore, limx→0 fx=f0or limx→0 3x-12sinxln1+x=f0or f0=limx→0 3x-1x2xsinxxln1+xx=ln 32