The function fx=x+1x3+1 can be written as the sum of an even function g(x) and an odd function h(x). Then the value of g0 is _________
gx=fx+f-x2 = 121x2-x+1+11+x+x2 = 122x2+1x2+12-x2 = x2+1x4+x2+1∴ g0=1