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Questions  

 The function f(x)=|x3|,x1x243x2+134,x<1

a
discontinuous at  x = 1
b
not differentiable at x = 1
c
continuous and differentiable at x = 1
d
continuous at x = 1 but not derivable at x  = 1 .

detailed solution

Correct option is C

f'1−    =limx→1−f(x)−f(1)x−1                    =limx→1x24−3x2+134−2x−1                   = limx→1x2−6x+54(x−1)                  =limx→1(x−5)(x−1)4(x−1)=limx→1(x−5)4=−1f'1+=limx→1+f(x)−f(1)x−1limx→13−x−2x−1=−1∴f'(1)=−1∴f(x) is derivable and hence continuous also at x=1

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