Q.
The function f(x)=|x−3|,x≥1x24−3x2+134,x<1
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a
discontinuous at x = 1
b
not differentiable at x = 1
c
continuous and differentiable at x = 1
d
continuous at x = 1 but not derivable at x = 1 .
answer is C.
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Detailed Solution
f'1− =limx→1−f(x)−f(1)x−1 =limx→1x24−3x2+134−2x−1 = limx→1x2−6x+54(x−1) =limx→1(x−5)(x−1)4(x−1)=limx→1(x−5)4=−1f'1+=limx→1+f(x)−f(1)x−1limx→13−x−2x−1=−1∴f'(1)=−1∴f(x) is derivable and hence continuous also at x=1
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