Questions
A function whose graph is symmetrical about the origin is given by
a
f (x) = (3x + 3– x)
b
f(x)=coslogx+1+x2
c
f (x + y) = f (x) + f (y) ∀ x, y ∈ R
d
None of these
detailed solution
Correct option is C
A function whose graph is symmetrical about the origin must be odd.(3x + 3–x) is an even function.Since cos x is an even function and logx+1+x2 is an odd function,∴coslogx+1+x2 is an even function.If f (x + y) = f (x) + f (y) ∀ x, y ∈ R, then f (x) must be odd.Talk to our academic expert!
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