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The functions f and g are given by $f (x) = {x}$ the fractional part of $x$ and $g (x) = \frac{1}{2} \sin [x] π,$ where $[x]$ denotes the integral part of $x .$ Then range of $g o f$ is

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Correct option is B

(gof)(x)=g(f(x))=12sin[{x}]π=0, for all x ∈ R. Hence the range of gof is {0}.

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The functions f and g are given by f(x)={x} the fractional part of x and g(x)=12sin⁡[x]π, where [x] denotes the integral part of x. Then range of gof is

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The functions f and g are given by $f (x) = {x}$ the fractional part of $x$ and $g (x) = \frac{1}{2} \sin [x] π,$ where $[x]$ denotes the integral part of $x .$ Then range of $g o f$ is