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G is the centroid of the triangle ABC and if G, is the centroid of another  triangle A1B1C1, then value of AA1+BB1+CC1 is : 

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a
G G→1
b
0
c
3 G G→1
d
None of these

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detailed solution

Correct option is C

Clearly  AA1→=AG→+GG1→+G1A1→B B1→  =  BG→ + GG→1 +G1 B1→CC1→ = CG→ + GG1→ + G1C1→ Adding  these __,AA1→+BB1→+CC1→=3GG1→ + (AG→ + BG→ + CG→) + (G1 A1→ + G1B1→ + G1C1→)=3GG1→ + (AG→ + 2DG→) + (G1 A1→ + 2G1D1→) (where AD and A1D1 are medians of the triangles ABC and A1B1C1 respectively.) =3GG1→ + (AG→ + GA→) + (G1 A1→ + A1G1→)=3GG1 → + 0→ + 0→ = 3GG1→


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