Questions
In a game called 'odd man out' , m (m > 2) persons toss a coin to determine who will buy refreshments for the
entire group. A person who gets an outcome different from that of the rest of the members of the group is
called the odd man out. The probability that there is a loser in any game is
Remember concepts with our Masterclasses.
80k UsersReady to Test Your Skills?
Check Your Performance Today with our Free Mock Tests used by Toppers!detailed solution
Correct option is B
Let A denote the event that there is an odd man out in a game. The total number of possible case s is 2m .A person is odd man out if he is alone in getting a head or a tail. The number of ways in which there is exactly one tail(head) and the rest are heads (tails) is mC1=mThus, the number of favorable ways is m + m - 2m. Therefore, P(A)=2m2m=m2m−1Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
